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Question 9.1: Consider a 3-MW wind turbine operating at a wind speed of 15......

Consider a 3-MW wind turbine operating at a wind speed of 15 m/s. Its global efficiency (turbine, gearbox, and generator) is supposed to be 30%. What should be the swept area and the size of the rotor?

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The power of the wind needs to be 3\times10^{6}/0.3=10^{7}\mathbf{W}. The power of the wind is given by P={\textstyle\frac{1}{2}}\rho A V^{3}, where ρ is the mass density of air (1.29 kg/ m³), A the area, and V the nominal speed of the wind (15 m/s). This gives area A = 4594 m²  . The rotor diameter is 76.5 m.

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