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Question 16.CSGP.93: Consider air at 2600 K, 1 MPa. Find the equilibrium concentr......

Consider air at 2600 K, 1 MPa. Find the equilibrium concentration of NO neglecting dissociations of oxygen and nitrogen.

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1 \,kmol \text { air }\left(0.78 \,N _2, 0.21 O _2, 0.01 \,Ar \right) \text { at } 2600 \,K , 1\, MPa \text {. }

\begin{array}{cccl|l}N _2+ &O _2 \quad \Leftrightarrow & 2 NO & Ar & n _{ N 2}=0.78- x \\0.78 & 0.21 & 0 & 0.01 & n _{ O 2}=0.21- x \\- x & – x & +2 x & & n _{ NO }=2 x , \quad n _{ ar }=0.01 \\\hline 0.78- x & 0.21- x & 2 x & 0.01 & n _{ tot }=1.0\end{array}

From A.11 at 2600 K, ln K = -5.316, K = 0.0049124

\begin{aligned}& K =\frac{4 x ^2}{(0.78- x )(0.21- x )}\left(\frac{ P }{ P ^0}\right)^0 \quad \Rightarrow \\& \frac{ x ^2}{(0.78- x )(0.21- x )}=\frac{0.0049124}{4}=0.001228 \quad \text { and } 0< x <0.21\end{aligned}

Solve for x:      x =0.0136 \quad \Rightarrow \quad y _{ NO }=\frac{2 x }{1.0}= 0 . 0 2 7 2

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