Question 15.6: Consider the reaction at chemical equilibrium: 2 KClO3(s)→←2......
Consider the reaction at chemical equilibrium:
2\operatorname{KClO_{3}}(s) \rightleftarrows 2\operatorname{KCl}(s)\,+\,3\operatorname{O}_{2}(g)What is the effect of decreasing the volume of the reaction mixture? Increasing the volume of the reaction mixture?
Step-by-Step
the reaction to shift to the left (toward the side with fewer moles of gas particles). Increasing the volume of the reaction mixture decreases the pressure and causes the reaction to shift to the right (toward the side with more moles of gas particles).
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