Deduce the structure of the following compound based on the molecular formula and the following proton NMR spectrum.
The singlet of intensity 3H at 2.1 ppm is due to a methyl group bonded to the carbonyl carbon atom. The triplets of intensity 2H at 3.5 and 4.4 ppm are due to neighboring methylene groups that are also bonded to an oxygen atom and a bromine atom, respectively. The compound is bromoethyl ethanoate.