Question 2.16: Density as a Conversion Factor The gasoline in an automobile......

Density as a Conversion Factor

The gasoline in an automobile gas tank has a mass of 60.0 kg and a density of 0.752 g/cm^3. What is its volume in cm^3?

Step-by-Step
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SORT

You are given the mass in kilograms and asked to find the volume in cubic centimeters. Density is the conversion factor between mass and volume.

GIVEN: 60.0 kg

density = 0.752 g/cm^3

FIND: volume in cm^3

STRATEGIZE

Build the solution map starting with kg and ending with cm^3. Use the density (inverted) to convert from g to cm^3.

SOLUTION MAP

kg  \underset{\frac{1000  g}{1  kg} }{\longrightarrow } g \underset{\frac{1  cm^3}{0.752  g} }{\longrightarrow } cm^3

RELATIONSHIPS USED

0.752 g/cm^3 (given in problem)

1000 g = 1 kg (from Table 2.2)

SOLVE

Follow the solution map to solve the problem. Round the answer to three significant figures to reflect the three significant figures in the given quantities.

SOLUTION

60.0  \cancel{ kg}\times \frac{1000  \cancel{ g}}{1  \cancel{ kg}}\times \frac{1  cm^3}{0.752  \cancel{ g}} = 7.98 \times 10^4  cm^3

CHECK

Check your answer. Are the units correct? Does the answer make physical sense?

The units of the answer are those of volume, so they are correct. The magnitude seems reasonable because the density is somewhat less than 1 g/cm^3; therefore, the volume of 60.0 kg should be somewhat more than 60.0 × 10^3 cm^3.

Table 2.2

SI Prefix Multipliers
Prefix Symbol Meaning Multiplier
tera- T trillion 1,000,000,000,000 (10^{12})
giga- G billion 1,000,000,000 (10^{9})
mega- M million 1,000,000 (10^{6})
kilo- k thousand 1,000 (10^{3})
hecto- h hundred 100 10^{2}
deca- da ten 10 10^{1}
deci- d tenth 0.1 (10^{-1})
centi- c hundredth 0.01 (10^{-2})
milli- m thousandth 0.001 (10^{-3})
micro- µ millionth 0.000001 (10^{-6})
nano- n billionth 0.000000001 (10^{-9})
pico- p trillionth 0.000000000001 (10^{-12})
femto- f quadrillionth 0.000000000000001 (10^{-15})

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