Question 9.3.1: Determination of a Heat of Reaction from Heats of Formation ......

Determination of a Heat of Reaction from Heats of Formation
Determine the standard heat of reaction for the combustion of liquid n-pentane, assuming H_{2}O(l) is a combustion product.

C_{5}H_{12}(l) + 8O_{2}(g) → 5CO_{2}(g) + 6H_{2}O(l)

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From Equation 9.3-1

\boxed{ΔH^{°}_{r} = \sum\limits_{i}{\nu _{i}\Delta \hat{H}^{°}_{fi}} = \sum\limits_{products}{\left|\nu _{i}\right| \Delta \hat{H}^{°}_{fi}}- \sum\limits_{reactants}{\left|\nu _{i}\right| \Delta \hat{H}^{°}_{fi}}}              (9.3-1)
\begin{matrix}ΔH^{°}_{r} = 5  mol  CO_{2} (\Delta \hat{H}^{°}_{f})_{ CO_{2}(g)} + 6  mol  H_{2}O (\Delta \hat{H}^{°}_{f})_{ H_{2}O(l)}  –  1  mol  C_{5}H_{12}(\Delta \hat{H}^{°}_{f})_{C_{5}H_{12}(l)}  \\\\\left. \Large{\Downarrow} \right. Heats  of  formation  from  Table  B.1  or  APEx  \\\\ ΔH^{°}_{r} = [5(-  393.5)+6(- 285.84)  –  (- 173.0)]  kJ\\ = \boxed{- 3509  kJ}\end{matrix}

To verify the formula for ΔH°_{r}, we may write the stoichiometric equations for the formation reactions of the reactants and products:

1. 5C(s)+6H_{2}(g) \rightarrow C_{5}H_{12}(l):    ΔH^{°}_{r1} = 1  mol  C_{5}H_{12}(\Delta \hat{H}^{°}_{f})_{C_{5}H_{12}(l)}

2.  C(s)+ O_{2}(g) \rightarrow CO_{2}(g):    ΔH^{°}_{r2} = 1  mol  CO_{2} (\Delta \hat{H}^{°}_{f})_{ CO_{2}(g)}

3.  H_{2}(g)+ \frac{1}{2} O_{2}(g) \rightarrow H_{2}O (l):   ΔH^{°}_{r3} = 1   mol  H_{2}O (\Delta \hat{H}^{°}_{f})_{ H_{2}O(l)}

The desired reaction,
4. C_{5}H_{12}(l) + 8O_{2}(g) → 5CO_{2}(g) + 6H_{2}O(l):  ΔH^{°}_{r} = ?

may be obtained as 5 × (2) + 6 × (3) – (1) (verify), and the given formula for ΔH°_{r}then follows from Hess’s law.

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