Question 15.5: Determine for the bridge circuit the peak value of load curr......
Determine for the bridge circuit the peak value of load current when V_i = 15 V, R_1 = 600 Ω and the forward voltage drop of the diode is 0.7 V. Also calculate the average value of the output current
Step-by-Step
\begin{aligned} \mathrm{V}_{\mathrm{i}} & =15 \mathrm{~V} \\ \mathrm{~V}_{\mathrm{i}}(\max ) & =\sqrt{2} \times 15=21.21 \mathrm{~V} \end{aligned}
Maximum value of voltage appearing across the load will be V_i (max) – 2 V_F.
This is because two diodes are involved in the current flow through the load at any point of time
\begin{aligned} \mathrm{V}_0(\max ) & =\mathrm{V}_{\mathrm{i}}(\max )-2 \mathrm{~V}_{\mathrm{F}} \\ & =21.21-2 \times 0.7 \\ & =19.81 \mathrm{~V} \\ \mathrm{I}_0(\max ) & =\frac{\mathrm{V}_0(\mathrm{max})}{\mathrm{R}_{\mathrm{L}}}=\frac{19.81}{600}=36 \mathrm{~mA} \\ \mathrm{I}_0(\text { average }) & =\mathrm{I}_{\mathrm{dc}}=\frac{2 \mathrm{I}_{\mathrm{m}}}{\pi}=\frac{2 \times 36}{3.14}=22.93 \mathrm{~mA} \end{aligned}Related Answered Questions
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