Question 20.3: Determining the Oxidation State of the Metal in a Coordinati......

General Chemistry: Atoms First [1015060]

Determining the Oxidation State of the Metal in a Coordination Compound

What is the oxidation state of platinum in the coordination compound $K[Pt(NH_3)Cl_5]$ ?

STRATEGY

Because the compound is electrically neutral overall and contains one $K^+$ cation per complex anion, the anion must be $[Pt(NH_3)Cl_5]^-$ . Since ammonia is neutral and chloride has a charge of –1, the sum of the oxidation numbers is +1 + n + 0 + (5)(-1) = 0, where n is the oxidation number of Pt:

\begin{aligned}& \mathrm{K}^{+} \ \ \ \ \quad \mathrm{Pt}^{n+} \ \ \ \mathrm{NH}_3{ } \ \ \ \ \ \ \ \ \ \ \ \mathrm{5Cl}^{-} \\& +1 \ \ \ +n+ \ \ \ \ \ \ 0 \ \ \ \ \ \ +(5)(-1)=0 ; \quad \text { so, } n=+4\end{aligned}

fig20.3

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The oxidation state of platinum is +4.

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