Draw the structural formula(s) for the product(s) formed by oxidation of the following alcohols with a mild oxidizing agent. If no reaction occurs, write “no reaction.”
a. \begin{matrix} CH_{3}-CH_{2}-CH_{2}-\underset{|}{C}H-CH_{3} \\ \quad\quad\quad\quad\quad\quad \ \ OH \end{matrix} b. \begin{matrix} CH_{3}-\underset{|}{C}H-CH_{2}-OH \\ CH_{3} \quad\quad\quad \end{matrix}
c. \begin{matrix} CH_{3}-CH_{2}-\underset{|}{C}H-OH \\ \quad\quad\quad\quad CH_{3} \end{matrix} d.
a. The oxidation product will be a ketone, as this is a 2° alcohol.
b. A 1° alcohol undergoes oxidation first to an aldehyde and then to a carboxylic acid.
c. A ketone is the product from the oxidation of a 2° alcohol.
d. This cyclic alcohol is a tertiary alcohol. The hydroxyl-bearing carbon atom is attached to two ring carbon atoms and a methyl group. Tertiary alcohols do not undergo oxidation with mild oxidizing agents. Therefore, “no reaction.”