Question 6.10.9: Evaluating an Exponential Growth Function The world populati......

A Survey of Mathematics with Applications [1175400]

Evaluating an Exponential Growth Function

The world population in 2012 was about 7.046 billion people. Assume that the world population continues to grow exponentially at the growth rate of 1.2% per year. The expected world population, in billions of people, t years after 2012, is given by the formula P(t) = $7.046e^{0.012t}$ . Determine the expected world population in 2018.

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Since 2018 is 6 years after 2012, t = 6.

P(t) = $7.046e^{0.012t}$

P(6) = $7.046e^{0.012(6)}$

= $7.046e^{0.072}$

≈ 7.046(1.074655344)

≈ 7.572021554

Thus, in 2018, the world population is expected to be about 7.57 billion people.

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