Find an expression for dz in terms of dx and dy for the following functions:
(a) z = Ax^{a} + By^{b}; (b) z = e^{xu} \ \text{with} u = u(x, y);\ \text{ and} (c) z = ln(x^{2} + y).
(b) Arguing directly, using abbreviated notation that drops (x, y) throughout, one has
\mathrm{d}z=e^{x u}\,\mathrm{d}(x u)=e^{x u}(x\mathrm{d}u+u\,\mathrm{d}x)=e^{x u}\{x[u_{1}^{\prime}(x,y)\,\mathrm{d}x+u_{2}^{\prime}(x,y)\,\mathrm{d}y]+u\,\mathrm{d}x\}\quad=e^{x u}\{[x u_{1}^{\prime}(x,y)+u]\,\mathrm{d}x+x u_{2}^{\prime}(x,y)\,\mathrm{d}y\}
(\mathrm c)\ dz=d\ln(x^{2}+y)={\frac{\mathrm{d}(x^{2}+y)}{x^{2}+y}}={\frac{2x\,\mathrm{d}x+\mathrm{d}y}{x^{2}+y}}.