Find an expression for the voltage gain A_v = v_p/v_g of the basic triode amplifier of Fig. 4-12, using an ac equivalent circuit.
The equivalent circuit of Fig. 7-9(b) is applicable if R_L is connected from P to K. Then, by voltage division in the plate circuit,
v_{p} = {\frac{R_{L}}{R_{L} + r_{p}}}\left(-\mu v_{g}\right) \qquad \text{so} \qquad A_{v} = {\frac{v_{p}}{v_{g}}} = {\frac{-\mu R_{L}}{R_{L} + r_{p}}}