Find the elasticity of f(x)=Axb, where A and b are constants, with A=0.
In this case, f′(x)=Abxb−1.Hence,Elx(Axb)=(x/Axb)Abxb−1=b,so
f(x)=Axb ⇒ Elxf(x)=b (7.7.3)
The elasticity of the power function Axb w.r.t. x is simply the exponent b. So this function has constant elasticity. In fact, it is the only type of function which has constant elasticity. This is shown in Exercise 9.9.6.