Find the maximum stress on the section AB of the cramp when a pressure of 7500 N is exerted by the screw. The section is rectangular 2.5 cm by 1 cm. (Cambridge)
The section AB is subjected to a tension of 2500 N, and a bending moment (2500)(0 10) = 250 Nm. The area of the section = 0.25 × 10^{-3} m². The direct tensile stress = (2500)/(0.25 × ^{-3}) = 10 MN/m². The second moment of area = \frac{1}{12}(0.01)(0.025)³ = 13.02 × 10^{-9} m^4. Therefore, the maximum bending stresses due to the couple of 250 Nm are equal to
\frac{(250)(0.0125)}{(13.02 \times 10^{-9})} = 240 MN/m^2Hence the maximum tensile stress on the section is
(240 + 10) = 250 MN/m²
The maximum compressive stress is
(240 – 10) = 230 MN/m²