Find the phasor input VS in Figure P8-51 when the phasor output is {V}_{\mathrm{O}} = 200 + j100 V.
The output phasor voltage appears across two elements. Use the voltage and the values of those elements to determine their corresponding currents. Sum the currents to find the current flowing through the other two elements in series. Compute the total voltage across the source.
clear all
Vo = 200+100j;
Io1 = Vo/100;
Io2 = Vo/(-200j);
Is = Io1+Io2;
Vs = (10+20j)*Is + Vo
MagVs = abs(Vs)
PhaseVs = angle(Vs)*180/pi
Vs =
175.0000e+000 +150.0000e+000i
MagVs =
230.4886e+000
PhaseVs =
40.6013e+000
{V}_{\mathrm{S}}=175+j 150 \mathrm{~V}=230.4886 ~\angle ~40.60^{\circ} \mathrm{V}.