Find V, period T, frequency f, and peak-to-peak voltage V_{p-p} of the voltage waveform shown (Fig. 11-23).
Use Eq. (11-9).
RMS value = 0.707 × peak value (11-9)
V = 0.707\ V_{M} = 0.707(48\ \mu V) = 33.9\ \mu VThe time for 1 cycle is 5 μs. Therefore,
T = 5\ \mu s = 5 \times 10^{-6}\ sf =\frac{1}{T} (11-4)
=\frac{1}{5 \times 10^{-6}}=200 \times 10^{3}\ Hz=200\ kHzThe ac wave is symmetric with respect to the horizontal axis. So
V_{p-p} = 2\ V_{M} = 2(48) = 96\ \mu V