Question 6.5: For the amplifier of Fig. 3-10(a), let vi = 0.25 sin(2000πt)......

For the amplifier of Fig. 3-10(a), let vi=0.25sin(2000πt) V, VCC=15 V, CC1=CC2=CC=100 μF, R1=6 kΩ, R2=50 kΩ, RC=RL=1 kΩv_i = 0.25 \sin(2000πt)  \text{V},  V_{CC} = 15  \text{V},  CC_1 = CC_2 = CC = 100  μF,  R_1 = 6  kΩ,  R_2 = 50  kΩ,  R_C = R_L = 1  kΩ, and Ri=RE=100 ΩR_i = R_E = 100  Ω. The transistor is characterized by the model of Problem 5.4. Use SPICE methods to determine the CE hybrid parameters of (6.5) through (6.8) for this transistor at the point of operation.

Input resistance                    hievBEiBQΔvBEΔiBQ{h_{i e} \equiv \frac{\partial v_{B E}}{\partial i_{B}}\bigg|_{_{Q}} \approx \frac{\Delta v_{B E}}{\Delta i_{B}}\bigg|_{_{Q}}}          (6.5)

Output admittance                    hoeiCvCEQΔiCΔvCEQh_{o e} \equiv {\frac{\partial i_C}{\partial v_{C E}}}{\bigg|}_{Q} \approx {\frac{\partial\Delta i_{C}}{\Delta v_{C E}}}{\bigg|}_{Q}          (6.8)

3.10
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The netlist code below describes the circuit.

EX6_5.CIR
vi       1 0 SIN(0V 250mV 10kHz)
Ri      1 2 100ohm
CC1   2 3 1000uF
CC2   4 7 1000uF
R1      3 0 6kohm
R2     3 6 50kohm
RC    6 4 1kohm
RE    5 0 100ohm
RL    7 0 1kohm
VCC 6 0 15V
Q 4   3 5 QNPNG
.MODEL QNPNG NPN(Is=10fA Ikf=150mA Isc=10fA Bf=150
+ Br=3 Rb=1ohm Rc=1ohm Va=75V Cjc=10pF Cje=15pF)
.TRAN 1us 0.1ms
.PROBE
.END

After executing 〈Ex6_5.CIR〉, the plots of Fig. 6-8 can be generated by use of the Probe feature of PSpice.    The resulting h-parameter value is indicated on each of the four plots of Fig. 6-8.

6.8

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