For the velocity potential Φ = x²— y² , find the velocity components at point (4, 5).
Given: Φ = x²— y²
We know that
\frac{\pmb{\delta} \phi }{\pmb{\delta}x }=u=2x
Hence, value of u at (4, 5) is:
u = 2x
= 2 × 4 = 8 units
Again, we know that
\frac{\pmb{\delta} \phi }{\pmb{\delta}y } = – v
= −(−2y) = 2y
Or v = −2y
= −2 × 5 = −10 units