Question 9.CC.4: How many grams of zinc metal will react with 0.315 L of a 1.......

How many grams of zinc metal will react with 0.315 L of a 1.20 M HCl solution?

2 HCl (a q)+ Zn (s) \longrightarrow H _2(g)+ ZnCl _2(a q)
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0.315\ \cancel{L \text { solution }} \times \frac{1.20\cancel{ \text { moles } HCl} }{1\ \cancel{L \text { solution }}} \times \frac{1 \cancel{\text { mole } Zn} }{2\cancel{ \text { moles } HCl} } \times \frac{65.41\ g\ Zn }{1\cancel{ \text { mole } Zn}}

= 12.4 g of Zn

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