Question 3.CC.5: How many joules are required to heat 5.25 g of titanium from......
How many joules are required to heat 5.25 g of titanium from 85.5 °C to 132.5 °C?
Step-by-Step
m=5.25\ g ,\, \Delta T=132.5\ ^{\circ} C -85.5\ ^{\circ} C =47.0\ ^{\circ} C
SH for titanium = 0.523 J/g °C
The known values are substituted into the heat equation making sure units cancel.
\begin{aligned} \text { Heat } & =m \times \Delta T \times S H=5.25\ \cancel g \times 47.0\ ^{\circ} \cancel{C} \times \frac{0.523\ J }{ \cancel g\ ^{\circ} \cancel C } \\ & =129\ J \end{aligned}
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