If 12.5 g of S reacts with 17.2 g of O2, what is the limiting reactant and the mass, in grams, of SO3 produced? 2S(s) + 3O2(g)→2SO3(g)

Question

If 12.5 g of S reacts with 17.2 g of O[latex]_{2}[/latex], what is the limiting reactant and the mass, in grams, of SO[latex]_{3}[/latex] produced?

[latex] 2 S ( s )+3 O _2( g ) \longrightarrow 2 SO _3( g ) [/latex]

Accepted Answer

Mass of SO[latex]_3[/latex] from S:

[latex] \underset{ ext{Three SFs}}{12.5\cancel{ g\ S}} imes \underset{ ext{Four SFs}}{\overset{ ext{Exact}}{\frac{1\cancel{ ext { mole } S} }{32.07\cancel{ g\ S} }}} imes \underset{ ext{Exact}}{\overset{ ext{Exact}}{\frac{2 \cancel{ ext { moles } SO _3}}{2\cancel{ ext { moles } S} }}} imes \underset{ ext{Exact}}{\overset{ ext{Four SFs}}{\frac{80.07\ g\ SO _3}{1 \cancel{ ext { mole SO}_3}}}}=\underset{ ext{Three SFs}}{31.2\ g ext{ of }SO _3 }[/latex]

Mass of SO[latex]_3[/latex] from O[latex]_2[/latex] :

[latex] \underset{ ext{Three SFs}}{17.2\cancel{ g\ O_2}} imes \underset{ ext{Four SFs}}{\overset{ ext{Exact}}{\frac{1\cancel{ ext { mole } O_2} }{32.00\cancel{ g\ O_2} }}} imes \underset{ ext{Exact}}{\overset{ ext{Exact}}{\frac{2 \cancel{ ext { moles } SO _3}}{3\cancel{ ext { moles }O_2} }}} imes \underset{ ext{Exact}}{\overset{ ext{Four SFs}}{\frac{80.07\ g\ SO _3}{1 \cancel{ ext { mole SO}_3}}}}\ ext{Limiting reactant}=\underset{ ext{Three SFs}}{28.7\ g ext{ of }SO _3 }\quad ext{Smaller amount of SO}_3[/latex]

Question 7.CC.9: If 12.5 g of S reacts with 17.2 g of O2, what is the limitin......

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