If \mathbf{a}=3 t^2 \mathbf{i}+\cos 2 t \mathbf{j}, find
(a) \frac{\mathrm{d} \mathbf{a}}{\mathrm{d} t} (b) \left|\frac{\mathrm{d} \mathbf{a}}{\mathrm{d} t}\right| (c) \frac{\mathrm{d}^2 \mathbf{a}}{\mathrm{d} t^2}
(a) If \mathbf{a}=3 t^2 \mathbf{i}+\cos 2 t \mathbf{j}, then differentiation with respect to t yields
\frac{\mathrm{d} \mathbf{a}}{\mathrm{d} t}=6 t \mathbf{i}-2 \sin 2 t \mathbf{j}(b) \left|\frac{\mathrm{d} \mathbf{a}}{\mathrm{d} t}\right|=\sqrt{(6 t)^2+(-2 \sin 2 t)^2}=\sqrt{36 t^2+4 \sin ^2 2 t}
(c) \frac{\mathrm{d}^2 \mathbf{a}}{\mathrm{d} t^2}=6 \mathbf{i}-4 \cos 2 t \mathbf{j}