Question 1.TE.22: If the speed of light is 3.0 × 10^8 ms^-1, calculate the dis......
If the speed of light is 3.0 × 10^8\ \text{ms}^{-1}, calculate the distance covered by light in 2.00 ns.
Step-by-Step
Distance covered by light = Speed × Time
= 3.0 \times 10^8\ \text{ms}^{-1} \times 2.00\ \text{ns}\ \times \left\lgroup \frac{10^{-9}}{1\ \text{ns}} \right\rgroup
= 6.00 × 10^{-1} m = 0.600 m
Related Answered Questions
Question: 1.EP.13
Verified Answer:
Refer Conceptual Questions \fbox{3}...
Question: 1.TE.21
Verified Answer:
(a) Fixing the mass of dinitrogen as 14 g, the mas...
Question: 1.TE.20
Verified Answer:
(i) 34.2 (ii) 10.4 (iii) 0.0460 ...
Question: 1.TE.19
Verified Answer:
(i) 2 (ii) 3 ...
Question: 1.TE.18
Verified Answer:
Refer Solved Example 2 (Page 15).
Question: 1.TE.17
Verified Answer:
(i) 15 ppm means that 15 parts of chloroform is pr...
Question: 1.TE.16
Verified Answer:
The significant figures in a number are all the ce...
Question: 1.TE.15
Verified Answer:
(i) micro – 10^{-6} (ii) deca – 10 ...
Question: 1.TE.14
Verified Answer:
The SI unit of mass is kilogram (kg). Kilogram is ...
Question: 1.TE.13
Verified Answer:
Pressure is force (i.e., weight) acting per unit a...