Image of a Rectangle under a Linear Mapping
Find the image of the rectangle with vertices −1+i, 1+i, 1+2i, and −1+2i under the linear mapping f(z)=4iz+2+3i.
Let S be the rectangle with the given vertices and let S′ denote the image of S under f. We will plot S and S′ in the same copy of the complex plane. Because f is a linear mapping, our foregoing discussion implies that S′ has the same shape as S. That is, S′ is also a rectangle. Thus, in order to determine S′, we need only find its vertices, which are the images of the vertices of S under f:
f(−1+i)=−2−i f(1+i)=−2+7i
f(1+2i)=−6+7i f(−1+2i)=−6−i.
Therefore, S′ is the rectangle with vertices −2−i, −2+7i, −6+7i, and −6−i.