Question 9.CSGP.157: In a heat-powered refrigerator, a turbine is used to drive t......

In a heat-powered refrigerator, a turbine is used to drive the compressor using the same working fluid. Consider the combination shown in Fig. P9.157 where the turbine produces just enough power to drive the compressor and the two exit flows are mixed together. List any assumptions made and find the ratio of mass flow rates \dot{ m }_3 / \dot{ m }_1 \text { and } T _5\left( x _5\right. if in two-phase region) if the turbine and the compressor are reversible and adiabatic

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CV: compressor

\begin{aligned}& s _{2 S }= s _1=1.0779 \,kJ / kg K \rightarrow h _{2 S }=317.43 \,kJ / kg \\& w _{ SC }= h _1- h _{2 S }=271.89-317.43=-45.54 \,kJ / kg\end{aligned}

CV: turbine

\begin{aligned}& s _{4 S }= s _3=1.0850 \,kJ / kgK \text { and } P _{4 S } \Rightarrow h _{4 S }=319.72 \,kJ / kg \\& w _{ ST }= h _3- h _{4 S }=341.29-319.72=21.57 \,kJ / kg\end{aligned}

\text { As } \dot{ w }_{ TURB }=-\dot{ w }_{ COMP }, \quad \dot{ m }_3 / \dot{ m }_1=-\frac{ w _{ SC }}{ w _{ ST }}=\frac{45.54}{21.57}= 2 . 1 1 1

CV: mixing portion

\begin{aligned}& \dot{ m }_1 h _{2 S }+\dot{ m }_3 h _{4 S }=\left(\dot{ m }_1+\dot{ m }_3\right) h _5 \\& 1 \times 317.43+2.111 \times 319.72=3.111 h _5 \\& \Rightarrow h _5=318.984 \,kJ / kg \quad \Rightarrow \quad T _5= 5 8 . 7 ^ { \circ }  { C }\end{aligned}

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