# Question 1.SGPYQ.7: In the given figure, the value of R is (a) 10 Ω (b) 18 Ω (c)......

In the given figure, the value of R is

(a) 10 Ω        (b) 18 Ω

(c) 24 Ω        (d) 12 Ω

Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

The equivalent circuit is

Applying nodal analysis at V:

\begin{aligned} & =\frac{V-100}{14}+\frac{V}{2}+\frac{V-40}{1}=0 \\ & V-100+7 V+14 V-560=0 \\ & V=\frac{660}{22}=30 V \end{aligned}

Current through 14 Ω and 1 Ω resistors

\begin{aligned} & I_2=\frac{100-30}{14}=\frac{70}{14}=5 A \\ & I_1=\frac{40-30}{1}=10 A \end{aligned}

Therefore, current through R is 5 A (as 10 = 5 + 5)
So,

$\begin{gathered} \frac{100-40}{R}=5 \\ R=\frac{60}{5}=12 \Omega \end{gathered}$

## Related Answered Questions

Question: 1.SGPYQ.27

## Verified Answer:

 i_{ L }\left(0^{-}\right)=\frac{\text { To...
Question: 1.SGPYQ.28

## Verified Answer:

$E_1$ is the stored energy and [lat...
Question: 1.SGPYQ.26

## Verified Answer:

To find the Thevenin voltage open circuit the term...
Question: 1.SGPYQ.1

## Verified Answer:

Power is the rate of change of energy. Therefore, ...
Question: 1.SGPYQ.2

## Verified Answer:

Applying Kirchhoff’s current law, sum of incoming ...
Question: 1.SGPYQ.3

## Verified Answer:

Given that  Z_1=10 \angle-60^{\circ}, Z_2=1...
Question: 1.SGPYQ.4

## Verified Answer:

Given that for resonance  \left|V_{ L }\rig...
Question: 1.SGPYQ.5

## Verified Answer:

At node P,  \begin{aligned} & 2+\frac{V...
Question: 1.SGPYQ.6

## Verified Answer:

For maximum power transfer,  R_{ L }=\left|...
Question: 1.SGPYQ.8

## Verified Answer:

At t < 0;  V_C\left(0^{-}\right)=0 ; \qu...