Let x_1(t) \leftrightarrow X_1(\omega) \text { and } x_2(t) \leftrightarrow X_2(\omega) be two signals whose Fourier transforms are as shown in the figure below. In the figure, h(t)=e^{□ 2|t|} denotes the impulse response. For the given system, the minimum sampling rate required to sample y(t), so that y(t) can be uniquel reconstructed from its samples, is
(a) 2 B_1 (b) 2\left(B_1+B_2\right)
(c) 4\left(B_1+B_2\right) (d) ∞
For the given system:
Y(j \omega)=\left[X_1(j \omega)^* X_2(j \omega)\right] H(j \omega)
Bandwidth of X_1=B_1 and bandwidth of X_2=B_2 therefore, bandwidth of
X_1 * X_2=B_1+B_2
Therefore, bandwidth of
Y(j \omega)=B_1+B_2
Hence sampling frequency \geq 2\left(B_1+B_2\right)