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Question 17.9: Methanol (CH3OH), an important alcohol used in the manufactu......

Methanol (CH_{3}OH), an important alcohol used in the manufacture of adhesives, fibers, and plastics, is synthesized industrially by the reaction

CO(g) + 2  H_{2}(g)\xrightleftharpoons{} CH_{3}OH(g)

Use the thermodynamic data in Appendix B to calculate the equilibrium constant for this reaction at 25 °C.

STRATEGY

First calculate ΔG° for the reaction from the tabulated values of ΔG°_{f} for the reactants and products. Then use the equation ΔG° = -RT ln K to find the value of the equilibrium constant.

IDENTIFY
Known Unknown
Standard free energies of formation (ΔG°_{f}) Equilibrium constant (K_{p})
T = 25 °C
Step-by-Step
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ΔG° = ΔG°_{f}(CH_{3}OH)  –  [ΔG°_{f}(CO)  +  2  ΔG°_{f}(H_{2})]

= (1 mol)(-162.3 kJ/mol) – [(1 mol)(-137.2 kJ/mol) + (2 mol)(0 kJ/mol)]

ΔG° = -25.1 kJ

Solving the equation ΔG° = -RT ln K

for ln K gives                ln  K=\frac{-ΔG°}{RT}=\frac{-(-25.1\times 10^{3}  J/mol)}{[8.314  J/(K  \cdot  mol)](298  K)}=10.1

Therefore,                     K = K_{p} = antiln  10.1 = e^{10.1} = 2\times 10^{4}

The equilibrium constant obtained by this procedure is K_{p} because the reactants and products are gases and their standard states are defined in terms of pressure. If we want the value of K_{c}, we must calculate it from the relation K_{p}=K_{c}(RT)^{\Delta n} (Section 14.3), where R must be expressed in the proper units [R = 0.082 06 (L · atm)/(K · mol)].

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