MOSFET Q-Point Calculation
Determine the Q point for the MOSFET in the circuit of Figure 11.7.
Known Quantities: MOSFET drain resistance; drain and gate supply voltages; MOSFET equations.
Find: MOSFET quiescent drain current i_{DQ} and quiescent drain-source voltage v_{DSQ} .
Schematics, Diagrams, Circuits, and Given Data: V_{GG} = 2.4 V ; V_{DD} = 10 V; V_{T} = 1.4 V ; K = 48.5 mA/V²; R_{D} = 100 \Omega .
Assumptions: Use the MOSFET equations 11.2 through 11.4 as needed.
i_D = 0 \quad\text{Cutoff region} (11.2)
i_D = K[2(v_{GS} − V_T )v_{DS} − v^2_{DS} ] \quad Triode or ohmic region (11.4)
Analysis: The gate supply V_{GG} ensures that v_{GSQ} = V_{GG} = 2.4 V . Thus, v_{GSQ} \gt V_T . We assume that the MOSFET is in the saturation region, and we proceed to use equation 11.3 to calculate the drain current:
\begin{aligned} i_D &= K(v_{GS} − V_T )^2\left(1 + \frac{v_{DS}}{V_A}\right) \\ &\cong K(v_{GS} − V_T )^2 \end{aligned} \quad Saturation region (11.3)
i_{DQ} = K(v_{GS} − V_T )^2 = 48.5(2.4 − 1.4) = 48.5 mA
Applying KVL to the drain loop, we can calculate the quiescent drain-to-source voltage as:
v_{DSQ} = V_{DD} − R_D i_{DQ} = 10 − 100 \times 48.5 \times 10^{−3} = 5.15 V
Now we can verify the assumption that the MOSFET was operating in the saturation region. Recall that the conditions required for operation in region 2 (saturation) were v_{GS} \gt V_T and v_{GD} \lt V_T . The first condition is clearly satisfied. The second can be verified by recognizing that v_{GD} = v_{GS} + v_{SD} = v_{GS} – v_{DS} = – 2.75 V . Clearly, the condition v_{GD} \gt V_T is also satisfied, and the MOSFET is indeed operating in the saturation region .