Question 3.30: Plot the currents carried by each diode in a bridge rectifie......

From Figs. 3.38(c) and (d), we have $V_{out}=-V_{in}+2V_{D,on}$ for $V_{in}$< $-V_{D,on}$ and $V_{out}=V_{in}-2V_{D,on}$ for $V_{in}$ > $+2V_{D,on}$. In each half cycle, two of the diodes carry a current equal to $V_{out}/R_{L}$ and the other two remain off. Thus, the diode currents appear as shown in Fig. 3.41.