Predict the shape and the H–O–H bond angles for a hydronium ion, H_{3}O^{+}.
The Lewis formula for a H_{3}O^{+} ion is
\begin{bmatrix} H -\overset{..}{O}- H \\\overset{|}{H} \end{bmatrix} ^{\oplus }There are three hydrogen ligands and one lone pair attached to the central oxygen atom. Thus, it belongs to the class AX_{3}E. We see from Table 8.2 that it has a trigonal pyramidal shape. The H–O–H bond angles for a H_{3}O^{+} ion will be somewhat less than that of an ideal tetrahedron and so we predict that the angle is <109.5°.
TABLE 8.2 Molecular shapes. the white spheres represent the central atom, the red spheres represent ligands, and the green lobes represent lone pairs. | |||||
Molecular class | Ideal shape | Examples | Molecular class | Ideal shape | Examples |
AX_{2} | ![]() |
CO_{2},\ HCN,\ BeCl_{2} | AX_{4}E | ![]() |
SF_{4},\ XeO_{2}F_{2},\ IF^{+}_{4}, IO_{2}F^{–}_{2} |
AX_{3} | ![]() |
SO_{3},\ BF_{3},\ NO_{3}^{–},\ CO_{3}^{2–} | AX_{3}E_{2} | ![]() |
CIF_{3},\ BrF_{3} |
AX_{2}E | ![]() |
SO_{2},\ O_{3},\ PbX_{2},\ SnX_{2} (where X is a halogen) |
AX_{2}E_{3} | ![]() |
XeF_{2},\ I^{–}_{3},\ IF^{–}_{2} |
AX_{4} | ![]() |
SiH_{4},\ CH_{4},\ SO_{4}^{2–},\ ClO_{4}^{–},\ PO^{3-}_{4},\ XeO_{4} | AX_{6} | ![]() |
SF_{6},\ IOF_{5} |
AX_{3}E | ![]() |
NH_{3},\ PF_{3},\ AsCl_{3}, ClO^{–}_{3},\ H_{3}O^{+},\ XeO_{3} | AX_{5}E | ![]() |
IF_{5},\ TeF_{5}^{–},\ XeOF_{4} |
AX_{2}E_{2} | ![]() |
H_{2}O,\ OF_{2},\ SF_{2} | AX_{4}E_{2} | ![]() |
XeF_{4}, ICI_{4}^{-} |
AX_{5} | ![]() |
PCl_{5},\ AsF_{5},\ SOF_{4} |