Question 4.1: Solve the following equations: (a) 5x² =0 (b)2x² − 32 =0 (c)......

5x² = 0

x² = \frac{0}{5}

x² = 0

x = ±0

A repeated real
root (or solution)
x = 0, repeated

2x² − 32 = 0

2x² = 32

x² = 16

x = ±4

Two real roots
(or solutions)
x = –4, x = 4

2x² + 32 = 0

2x² = −32

x² = −16

x = ±\sqrt{-16}

∗   x = ±4i

Two imaginary roots
(or solutions)
x = 4i, x = –4i

2x² − 32x = 0

\underset{↓}{x} \underset{↓}{\underbrace{(2x – 32)}} = 0

x = 0      or

(2x − 32) = 0

x = \frac{32}{2} = 16

Two real roots
(or solutions)
x = 0 and x = 16