Specifications for the output voltage of a certain electric circuit are 48 to 52 V. The process is in control with \hat{\sigma} = 0.482\ V. Compute the process capability index C_{p}.
C_{p} = \frac{USL\ −\ LSL}{6\hat{\sigma}} = \frac{52\ −\ 48}{(6)(0.482)}
= 1.38
The process capability is potentially good.