Suppose that a thermal water reactor has a fuel temperature coefficient of –1 cent/°C, a moderator temperature coefficient of −0.5 cents/°C, and a leakage temperature coefficient of −0.1 cents/°C. If the temperature of all three materials is suddenly increased by 100°C, how much does the reactivity ρ fall in this case?
The total change in the reactivity is given by Δρ = α_MΔT_M + α_FΔT_F + α_LΔT_L. Since ΔT_M = ΔT_F = ΔT_L = 100 °C, the reactivity falls by Δρ = − (0.01 + 0.005 + 0.001) × 100 = −160 cents = −1.6 dollars in this case.