The Boolean function f implemented in the following figure using two input multiplexers is
(a) A\bar BC + AB\bar C (b) ABC + A\bar B \bar C
(c) \bar ABC + \bar A\bar B\bar C (d) \overline{AB}C + \bar AB\bar C
We know that
f = E · A
where E = \bar BC + B\bar C. Therefore, output f is given by
A\bar BC + AB\bar C
Ans. (a)