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Question 16.23: The complex power delivered to the load ZL in Figure P16-21 ......

The complex power delivered to the load Z_L in Figure P16-21 is 20 + j15 kVA. The load voltage is 2 kV(rms) and the line has an impedance of Z_W = 2 + j12 Ω per wire. Find the magnitude of the source voltage and the complex power produced by the source.

fig 16.21
Step-by-Step
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Use MATLAB to perform the calculations.

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Script File

clear all
SL = 20e3+15e3j;
VL = 2e3;
ZW = 2+12j;
% Find the magnitude of the current
MagIL = abs(SL/VL);
% Find the complex power in the wires
SW = 2*MagIL^2*ZW;
% Find the total complex power
Ss = SL+SW
% Find the magnitude of the source voltage
MagVs = abs(Ss)/MagIL
Ss =
20.6250e+003 + 18.7500e+003i
MagVs =
2.2299e+003

The magnitude of the source voltage is 2.2299 kV.

The complex power produced by the source is 20.625 + j18.75 kVA.

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