The reactances {\boldsymbol{x}}_{d} and x_{\boldsymbol{q}} of a salient-pole synchronous generator are 0.95 and 0.7 p.u., respectively. The armature resistance is negligible. The generator delivers rated kVA at unity PF and rated terminal voltage. Calculate the excitation voltage.
We apply
E_{f}^{\prime}=V_{t}+j I_{a}x_{q}As a result,
E_{f}^{\prime}=1+j(1)(0.7)=1.22\angle34.99\;\mathrm{deg}We now have
\begin{array}{c}{{I_{d}=I_{a}\sin34.99~\mathrm{deg}}}\\ {{=0.57~\mathrm{p.u.}}}\end{array}We can thus compute
\begin{array}{c}{{|E_{f}|=|E_{f}^{\prime}|+|I_{d}(x_{d}-x_{q})|}}\\ {{=1.22+0.57(0.25)}}\\ {{\delta=34.99\;\mathrm{deg}}}\end{array}Figure 7.32 pertains to this example.