The rectangular channel in Fig. 12–27a is made of unfinished concrete and has a slope of S_0 = 0.035. When it reaches the check dam, the flow backs up as shown in Fig. 12–27b. At a specific location before the dam, the water has a depth of 1.25 m and the flow is Q = 0.75 m³/s. Classify the surface profile for the flow. Take n = 0.014.
Fluid Description. The flow is steady and nonuniform. The water is considered incompressible.
Analysis. To classify the surface profile, we must determine the critical depth y_c, the normal flow depth y_n, and the critical slope S_c. Using Eq. 12–7, with q = Q/b = (0.75 m³/s)/(2 m) = 0.375 m²/s,
Since y = 1.25 m > y_c = 0.2429 m, the flow is subcritical. The depth y_n that will produce normal or uniform flow for Q = 0.75 m³/s is determined from the Manning equation. Since
P = (2y_n + 2 m)
then Eq. 12–20 becomes
\frac{y_n^{5/3}}{(2y_n + 2 m)^{2/3}} = 0.017678
Solving by trial and error, or using a numerical
procedure, we get
y_n = 0.1227 m
The critical slope is now determined from Eq. 12–22,
= 0.004118
Since y = 1.25 m > y_c > y_n and S_0 = 0.035 > S_c, then according to Table 12–2 the water surface in Fig. 12–27 is an S1 profile.
TABLE 12–2 Surface Profile Classification
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