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Question 2014.S2.50: The SOP (sum of products) form of a Boolean function is Σ(0,......

The SOP (sum of products) form of a Boolean function is Σ(0,1,3,7,11), where inputs are A,B,C,D (A is MSB, and D is LSB). The equivalent minimised expression of the function is

(a) (\bar{B}+C)(\bar{A}+C)(\bar{A}+\bar{B})(\bar{C}+D)

(b) (\bar{B}+C)(\bar{A}+C)(\bar{A}+\bar{C})(\bar{C}+D)

(c)(\bar{B}+C)(\bar{A}+C)(\bar{A}+\bar{C})(\bar{C}+\bar{D})

(d) (\bar{B}+C)(A+\bar{B})(\bar{A}+\bar{B})(\bar{C}+D)

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The K-map for the function is:

Minimised expression is,

F=(\bar{B}+C)(\bar{A}+C)(\bar{A}+\bar{B})(\bar{C}+D)

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