The torque given by Eq. (30.17) has a maximum magnitude at θ = 90° and at θ = -90°. What is the direction of the torque on the loop shown in Fig. 30.14 for θ = 90°? For θ = -90°?
\tau=\mu B \sin \theta (30.17)
For \theta = 90°, the direction of the cross product of \mu and B is out of the page; a torque out of the page implies that the loop will turn counterclockwise (right-hand rule). Similarly, for \theta = -90°, \tau is into the page; such a torque implies that the loop will turn clockwise.