The two identical boards are bolted together to form lhc beam. Determine the maximum spacing s of the bolts to the nearest mm if each boll has a shear strength of 15 kN.1l1e beam is subjected to a shear force of V = 50 kN.
Top (or bottom) board
Q=y^{\prime} A^{\prime}=0.05(0.1)(0.3)=1.5\left(10^{-3}\right) \mathrm{m}^{3}Two rows of nails
\begin{gathered} q_{\text {allow }}=2\left(\frac{F}{s}\right)=\frac{2\left[15\left(10^{3}\right)\right]}{s}=\frac{30\left(10^{3}\right)}{s} \\ q_{\text {allow }}=\frac{V Q}{I} ; \quad \frac{30\left(10^{3}\right)}{s}=\frac{50\left(10^{3}\right)\left[1.5\left(10^{-3}\right)\right]}{0.2\left(10^{-3}\right)} \\ s=0.08 \mathrm{~m}=80 \mathrm{~mm} \quad \text { } \end{gathered}