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Question 1.P.44: Thevenin equivalent resistance RTh for the given network is...

Thevenin equivalent resistance R_{ Th }  for the given network is

1.44
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From the given circuit, 2 A source is open circuit and 2 V source is short circuit.

R_{ Th }=16+\frac{12 \times 4}{16}=\frac{64+12}{4}=16+3=19  \Omega

1.44.1

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