Two identical 20-mm-thick plates arc bolted to the top and bottom flange to form the built-up beam. If the beam is subjected to a shear force of V = 300 kN, determine the maximwu spacing s of the bolts to the nearest mm if each bolt has a shear strength of 30 kN.
Consider large rectangle minus two side rectangles.
\begin{aligned} I & =\frac{1}{12}(0.2)\left(0.34^{3}\right)-(2) \frac{1}{12}(0.095)\left(0.28^{3}\right) \\ & =0.3075\left(10^{-3}\right) \mathrm{m}^{4} \end{aligned}Top plate
Q=y^{\prime} A^{\prime}=0.16(0.02)(0.2)=0.64\left(10^{-3}\right) \mathrm{m}^{3}Two rows of bolts
\begin{aligned} & q_{\text {allow }}=2\left(\frac{F}{s}\right)=\frac{2\left[30\left(10^{3}\right)\right]}{s}=\frac{60\left(10^{3}\right)}{s} \\ & q_{\text {allow }}=\frac{V Q}{I} ; \quad \frac{60\left(10^{3}\right)}{s}=\frac{300\left(10^{3}\right)\left[0.64\left(10^{-3}\right)\right]}{0.3075\left(10^{-3}\right)} \\ & s=0.09609 \mathrm{~m}=96.1 \mathrm{~mm} \\ & \text { Use } s=96 \mathrm{~mm} \quad \text { } \end{aligned}