Use the interaction method to determine the maximum load P that can be safely supported by the column of Concept Application 10.4 with an eccentricity of 0.8 in. The allowable stress in bending is 24 ksi.
The value of \left(\sigma_{\text {all }}\right)_{\text {centric }} has been determined and thus
\left(\sigma_{\text {all }}\right)_{\text {centric }}=19.99 ksi \quad\left(\sigma_{\text {all }}\right)_{\text {bending }}=24 ksi
Substituting these values into Eq. (10.57),
\frac{P / A}{\left(\sigma_{\text {all }}\right)_{\text {centric }}}+\frac{M c / I}{\left(\sigma_{\text {all }}\right)_{\text {bending }}} \leq 1 (10.57)
\frac{P / A}{19.99 ksi }+\frac{M c / I}{24 ksi } \leq 1.0
Use the numerical data from Concept Application 10.4 to write
\frac{P / 4}{19.99 ksi }+\frac{P(0.8)(1.0) / 1.333}{24 ksi } \leq 1.0
P ≤ 26.7 kips
The maximum load that can be safely applied is P = 26.7 kips.