What is the boiling point of a solution that contains 1.5 moles of the strong electrolyte KCl in 1.0 kg of water?
A solution of 1.5 moles of KCl in 1.0 kg of water contains 3.0 moles of solute particles (1.5 moles of K^+ and 1.5 moles of Cl^-) in 1.0 kg of water and has a boiling point change of
3.0 \cancel{\text { moles solute particles }} \times \frac{0.51\ ^{\circ} C }{1 \cancel{\text { mole solute particles }}}=1.53\ ^{\circ} CThe boiling point would be
100.00 °C + 1.53 °C = 101.53 °C.