What is the electron degeneracy pressure for relativistic electrons?

Question

Accepted Answer

The Fermi energy is now

[latex]E_{F} = p_{F} c[/latex], (36.13)

and the average internal energy density is

[latex]u =\frac{3}{4} nE_{F} =\frac{3c\hbar }{4} (3π^{2} )^{1/3} n^{4/3} .[/latex] (36.14)

The pressure [latex]p_{electron}[/latex] now follows from eqn 25.21 and is

[latex]p =\frac{u}{3}[/latex], (25.21)

[latex]p =\frac{u}{3} =\frac{c\hbar }{4} (3π^{2} )^{1/3} n^{4/3} .[/latex] (36.15)

Question 36.2: What is the electron degeneracy pressure for relativistic el......