Question 9.CC.2: What is the mass/volume percent (m/v) and the molarity (M) o......
What is the mass/volume percent (m/v) and the molarity (M) of 225 mL (0.225 L) of a LiCl solution that contains 17.1 g of LiCl?
Step-by-Step
\begin{aligned} & \begin{aligned}\text { Mass/volume percent }( m / v ) & =\frac{\text { grams of solute }}{\text { milliliters of solution }} \times 100 \% \\ & =\frac{17.1\ g\ LiCl }{225\ mL \text { solution }} \times 100 \% \\ & =7.60 \%( m / v ) LiCl \text { solution } \end{aligned} \\\\ & \text { moles of } LiCl =17.1 \cancel{g LiCl} \times \frac{1\ mole\ LiCl }{42.39 \cancel{g LiCl} } \\ & =0.403 \text { mole of LiCl } \\ & \text { Molarity }( M )=\frac{\text { moles of solute }}{\text { liters of solution }}=\frac{0.403 \text { mole LiCl }}{0.225\ L \text { solution }} \\ & =1.79\ M\ LiCl \text { solution } \end{aligned}
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