Question 20.2: What is the oxidation state of platinum in the coordination ......

Chemistry [1089329]

What is the oxidation state of platinum in the coordination compound $K[Pt(NH_{3})Cl_{5}]$ ?

STRATEGY

Because the compound is electrically neutral overall and contains one $K^{+}$ cation per complex anion, the anion must be $[Pt(NH_{3})Cl_{5}]^{-}$ . Since ammonia is neutral and chloride has a charge of -1, the sum of the oxidation numbers is +1 + n + 0 + (5)(-1) = 0, where n is the oxidation number of Pt:

K^{+}     Pt^{n+}     NH_{3}     5  Cl^{-}

+1 + n + 0 + (5)(-1) = 0; so, n = +4

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The oxidation state of platinum is +4.

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