What is the resistance of the following circuit as seen from the battery?
No current will flow through the two 4 Ω resistors, the two 3 Ω resistors, or the 7 Ω resistor. The current finds the path of least resistance through the high-lighted short-circuit segment of the circuit. Therefore, the circuit reduces to one 6 Ω in series with two 12 Ω in parallel.
R= 6 Ω+\frac{(12 Ω).(12 Ω)}{(12 Ω+12 Ω)}R = 6 Ω+6 Ω = 12 Ω