Question 8.8: What is the volume, in liters, of 64.0 g of O2 gas at STP?...

STEP 1   State the given and needed quantities.

Table 1

STEP 2   Write a plan to calculate the needed quantity.

STEP 3   Write the equalities and conversion factors including 22.4 L/mole at STP.

1 mole of O_{2} = 32.00 g of O_{2}          1 mole of O_{2} = 22.4 L of O_{2} (STP)

\frac{32.00 \space g \space O_{2}}{1 \space mole \space O_{2}}    and   \frac{1 \space mole \space O_{2}}{32.00 \space g \space O_{2}}                      \frac{22.4 \space L \space O_{2} \space(STP)}{1 \space mole \space O_{2}}    and   \frac{1 \space mole \space O_{2}}{22.4 \space L \space O_{2} \space(STP)}

STEP 4   Set up the problem with factors to cancel units.